IPL 2020: Mumbai Indians Rope In Trent Boult, Ankit Rajpoot To Play For Rajasthan Royals

Fast bowler Ankit Rajpoot will represent Rajasthan Royals in the 2020 edition of the Indian Premier League (IPL) after a successful trade by Kings XI Punjab. The right-arm fast bowler who joined KXIP in 2018 has played 23 IPL matches and has 22 wickets. Rajpoot put in one of the most memorable bowling performances ever when he claimed 5/14 in a league game in the 2018 season against SunRisers Hyderabad. Rajpoot is the only uncapped player to have a five-wicket haul in the IPL.

Young. Pacy. Dynamic. And now, a Royal!

Welcome to the #RoyalsFamily, @Ankit412rajpoot! #HallaBol pic.twitter.com/X4Z8F4Sbvm

— Rajasthan Royals (@rajasthanroyals) November 13, 2019

Left-arm fast bowler Trent Boult will play for Mumbai Indians in the upcoming season after being traded by Delhi Capitals. The seasoned New Zealand bowler made his IPL debut in 2014 and played for Delhi in the 2018 and 2019 season. He has 38 IPL wickets from 33 games.

Aala Re@trent_boult joins #MumbaiIndians from Delhi Capitals!#OneFamily #CricketMeriJaan pic.twitter.com/Sh1HQbiQ0N

— Mumbai Indians (@mipaltan) November 13, 2019

Mumbai Indians owner Akash Ambani while welcoming Boult to the franchise said, "Mumbai Indians has always taken pride in having good pace attack. Year-on-year our bowlers have won us many games, a classic example being last year's final".

"We are delighted to have Trent Boult as part of the MI family and are looking forward to the upcoming season. I am sure his experience across formats, especially in the limited overs, will add value to our campaign," he added.

Topics mentioned in this article

Mumbai Indians Rajasthan Royals Delhi Capitals Kings XI Punjab Trent Boult Cricket Ankit Rajpoot IPL 2020